Solve 2(x+7)^2=64

$$2 ( x + 7 ) ^ { 2 } = 64$$

Solve for x

$$x=4\sqrt{2}-7\approx -1.343145751$$

$$x=-4\sqrt{2}-7\approx -12.656854249$$

Steps by Finding Square Root

Divide both sides by 2.

$$\frac{2\left(x+7\right)^{2}}{2}=\frac{64}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$\left(x+7\right)^{2}=\frac{64}{2}$$

Divide 64 by 2.

$$\left(x+7\right)^{2}=32$$

Take the square root of both sides of the equation.

$$x+7=4\sqrt{2} x+7=-4\sqrt{2}$$

Subtract 7 from both sides of the equation.

$$x+7-7=4\sqrt{2}-7 x+7-7=-4\sqrt{2}-7$$

Subtracting 7 from itself leaves 0.

$$x=4\sqrt{2}-7 x=-4\sqrt{2}-7$$