Solve 2(x+1)^2-6=0

$$2 ( x + 1 ) ^ { 2 } - 6 = 0$$

Solve for x

$$x=\sqrt{3}-1\approx 0.732050808$$

$$x=-\left(\sqrt{3}+1\right)\approx -2.732050808$$

Steps by Finding Square Root

Add 6 to both sides of the equation.

$$2\left(x+1\right)^{2}-6+6=6$$

Subtracting 6 from itself leaves 0.

$$2\left(x+1\right)^{2}=6$$

Divide both sides by 2.

$$\frac{2\left(x+1\right)^{2}}{2}=\frac{6}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$\left(x+1\right)^{2}=\frac{6}{2}$$

Divide 6 by 2.

$$\left(x+1\right)^{2}=3$$

Take the square root of both sides of the equation.

$$x+1=\sqrt{3} x+1=-\sqrt{3}$$

Subtract 1 from both sides of the equation.

$$x+1-1=\sqrt{3}-1 x+1-1=-\sqrt{3}-1$$

Subtracting 1 from itself leaves 0.

$$x=\sqrt{3}-1 x=-\sqrt{3}-1$$