Solve 2(b+c)^2-3b

$$2 ( b + c ) ^ { 2 } - 3 b$$

Expand

$$2b^{2}+4bc-3b+2c^{2}$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(b+c\right)^{2}.

$$2\left(b^{2}+2bc+c^{2}\right)-3b$$

Use the distributive property to multiply 2 by b^{2}+2bc+c^{2}.

$$2b^{2}+4bc+2c^{2}-3b$$

Evaluate

$$2\left(b+c\right)^{2}-3b$$

Solution Steps

Use binomial theorem \left(p+q\right)^{2}=p^{2}+2pq+q^{2} to expand \left(b+c\right)^{2}.

$$2\left(b^{2}+2bc+c^{2}\right)-3b$$

Use the distributive property to multiply 2 by b^{2}+2bc+c^{2}.

$$2b^{2}+4bc+2c^{2}-3b$$