Solve 2(a-3)(a-1)(a+4)

$$2 ( a - 3 ) ( a - 1 ) ( a + 4 )$$

Evaluate

$$2\left(a^{3}-13a+12\right)$$

Solution Steps

Use the distributive property to multiply 2 by a-3.

$$\left(2a-6\right)\left(a-1\right)\left(a+4\right)$$

Apply the distributive property by multiplying each term of 2a-6 by each term of a-1.

$$\left(2a^{2}-2a-6a+6\right)\left(a+4\right)$$

Combine -2a and -6a to get -8a.

$$\left(2a^{2}-8a+6\right)\left(a+4\right)$$

Apply the distributive property by multiplying each term of 2a^{2}-8a+6 by each term of a+4.

$$2a^{3}+8a^{2}-8a^{2}-32a+6a+24$$

Combine 8a^{2} and -8a^{2} to get 0.

$$2a^{3}-32a+6a+24$$

Combine -32a and 6a to get -26a.

$$2a^{3}-26a+24$$

Expand

$$2a^{3}-26a+24$$

Solution Steps

Use the distributive property to multiply 2 by a-3.

$$\left(2a-6\right)\left(a-1\right)\left(a+4\right)$$

Apply the distributive property by multiplying each term of 2a-6 by each term of a-1.

$$\left(2a^{2}-2a-6a+6\right)\left(a+4\right)$$

Combine -2a and -6a to get -8a.

$$\left(2a^{2}-8a+6\right)\left(a+4\right)$$

Apply the distributive property by multiplying each term of 2a^{2}-8a+6 by each term of a+4.

$$2a^{3}+8a^{2}-8a^{2}-32a+6a+24$$

Combine 8a^{2} and -8a^{2} to get 0.

$$2a^{3}-32a+6a+24$$

Combine -32a and 6a to get -26a.

$$2a^{3}-26a+24$$