Solve 2(3x-y+4)=5y-2x-3

$$2 ( 3 x - y + 4 ) = 5 y - 2 x - 3$$

Solve for x

$$x=\frac{7y-11}{8}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by 3x-y+4.

$$6x-2y+8=5y-2x-3$$

Add 2x to both sides.

$$6x-2y+8+2x=5y-3$$

Combine 6x and 2x to get 8x.

$$8x-2y+8=5y-3$$

Add 2y to both sides.

$$8x+8=5y-3+2y$$

Combine 5y and 2y to get 7y.

$$8x+8=7y-3$$

Subtract 8 from both sides.

$$8x=7y-3-8$$

Subtract 8 from -3 to get -11.

$$8x=7y-11$$

Divide both sides by 8.

$$\frac{8x}{8}=\frac{7y-11}{8}$$

Dividing by 8 undoes the multiplication by 8.

$$x=\frac{7y-11}{8}$$

Solve for y

$$y=\frac{8x+11}{7}$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by 3x-y+4.

$$6x-2y+8=5y-2x-3$$

Subtract 5y from both sides.

$$6x-2y+8-5y=-2x-3$$

Combine -2y and -5y to get -7y.

$$6x-7y+8=-2x-3$$

Subtract 6x from both sides.

$$-7y+8=-2x-3-6x$$

Combine -2x and -6x to get -8x.

$$-7y+8=-8x-3$$

Subtract 8 from both sides.

$$-7y=-8x-3-8$$

Subtract 8 from -3 to get -11.

$$-7y=-8x-11$$

Divide both sides by -7.

$$\frac{-7y}{-7}=\frac{-8x-11}{-7}$$

Dividing by -7 undoes the multiplication by -7.

$$y=\frac{-8x-11}{-7}$$

Divide -8x-11 by -7.

$$y=\frac{8x+11}{7}$$