Solve 2(3-1)+3[1-2(2)]+2(4-1)(2+1)

$$2 ( 3 - 1 ) + 3 [ 1 - 2 ( 2 ) ] + 2 ( 4 - 1 ) ( 2 + 1 )$$

Evaluate

$$13$$

Solution Steps

Subtract 1 from 3 to get 2.

$$2\times 2+3\left(1-2\times 2\right)+2\left(4-1\right)\left(2+1\right)$$

Multiply 2 and 2 to get 4.

$$4+3\left(1-2\times 2\right)+2\left(4-1\right)\left(2+1\right)$$

Multiply 2 and 2 to get 4.

$$4+3\left(1-4\right)+2\left(4-1\right)\left(2+1\right)$$

Subtract 4 from 1 to get -3.

$$4+3\left(-3\right)+2\left(4-1\right)\left(2+1\right)$$

Multiply 3 and -3 to get -9.

$$4-9+2\left(4-1\right)\left(2+1\right)$$

Subtract 9 from 4 to get -5.

$$-5+2\left(4-1\right)\left(2+1\right)$$

Subtract 1 from 4 to get 3.

$$-5+2\times 3\left(2+1\right)$$

Multiply 2 and 3 to get 6.

$$-5+6\left(2+1\right)$$

Add 2 and 1 to get 3.

$$-5+6\times 3$$

Multiply 6 and 3 to get 18.

$$-5+18$$

Add -5 and 18 to get 13.

$$13$$

Factor

$$13$$