Solve 2(3)^3-3(3)^2-36(3)+14

$$2 ( 3 ) ^ { 3 } - 3 ( 3 ) ^ { 2 } - 36 ( 3 ) + 14$$

Evaluate

$$-67$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$2\times 3^{3}-3^{3}-36\times 3+14$$

Calculate 3 to the power of 3 and get 27.

$$2\times 27-3^{3}-36\times 3+14$$

Multiply 2 and 27 to get 54.

$$54-3^{3}-36\times 3+14$$

Calculate 3 to the power of 3 and get 27.

$$54-27-36\times 3+14$$

Subtract 27 from 54 to get 27.

$$27-36\times 3+14$$

Multiply 36 and 3 to get 108.

$$27-108+14$$

Subtract 108 from 27 to get -81.

$$-81+14$$

Add -81 and 14 to get -67.

$$-67$$

Factor

$$-67$$