Solve 2(3)^3+3(3)^2-23(3)-12

$$2 ( 3 ) ^ { 3 } + 3 ( 3 ) ^ { 2 } - 23 ( 3 ) - 12$$

Evaluate

$$0$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$2\times 3^{3}+3^{3}-23\times 3-12$$

Calculate 3 to the power of 3 and get 27.

$$2\times 27+3^{3}-23\times 3-12$$

Multiply 2 and 27 to get 54.

$$54+3^{3}-23\times 3-12$$

Calculate 3 to the power of 3 and get 27.

$$54+27-23\times 3-12$$

Add 54 and 27 to get 81.

$$81-23\times 3-12$$

Multiply 23 and 3 to get 69.

$$81-69-12$$

Subtract 69 from 81 to get 12.

$$12-12$$

Subtract 12 from 12 to get 0.

$$0$$

Factor

$$0$$