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2\left(2x+3\right)^{2}+9-9=19-9
Subtract 9 from both sides of the equation.
2\left(2x+3\right)^{2}=19-9
Subtracting 9 from itself leaves 0.
2\left(2x+3\right)^{2}=10
Subtract 9 from 19.
\frac{2\left(2x+3\right)^{2}}{2}=\frac{10}{2}
Divide both sides by 2.
\left(2x+3\right)^{2}=\frac{10}{2}
Dividing by 2 undoes the multiplication by 2.
\left(2x+3\right)^{2}=5
Divide 10 by 2.
2x+3=\sqrt{5} 2x+3=-\sqrt{5}
Take the square root of both sides of the equation.
2x+3-3=\sqrt{5}-3 2x+3-3=-\sqrt{5}-3
Subtract 3 from both sides of the equation.
2x=\sqrt{5}-3 2x=-\sqrt{5}-3
Subtracting 3 from itself leaves 0.
2x=\sqrt{5}-3
Subtract 3 from \sqrt{5}.
2x=-\sqrt{5}-3
Subtract 3 from -\sqrt{5}.
\frac{2x}{2}=\frac{\sqrt{5}-3}{2} \frac{2x}{2}=\frac{-\sqrt{5}-3}{2}
Divide both sides by 2.
x=\frac{\sqrt{5}-3}{2} x=\frac{-\sqrt{5}-3}{2}
Dividing by 2 undoes the multiplication by 2.