Solve 2(2+3)(4-3)^2-2(5-3)(3+4)

$$2 ( 2 + 3 ) ( 4 - 3 ) ^ { 2 } - 2 ( 5 - 3 ) ( 3 + 4 )$$

Evaluate

$$-18$$

Solution Steps

Add 2 and 3 to get 5.

$$2\times 5\left(4-3\right)^{2}-2\left(5-3\right)\left(3+4\right)$$

Multiply 2 and 5 to get 10.

$$10\left(4-3\right)^{2}-2\left(5-3\right)\left(3+4\right)$$

Subtract 3 from 4 to get 1.

$$10\times 1^{2}-2\left(5-3\right)\left(3+4\right)$$

Calculate 1 to the power of 2 and get 1.

$$10\times 1-2\left(5-3\right)\left(3+4\right)$$

Multiply 10 and 1 to get 10.

$$10-2\left(5-3\right)\left(3+4\right)$$

Subtract 3 from 5 to get 2.

$$10-2\times 2\left(3+4\right)$$

Multiply 2 and 2 to get 4.

$$10-4\left(3+4\right)$$

Add 3 and 4 to get 7.

$$10-4\times 7$$

Multiply 4 and 7 to get 28.

$$10-28$$

Subtract 28 from 10 to get -18.

$$-18$$

Factor

$$-18$$