Solve 2(1)^6+3(1)^4-1^2+3

$$2 ( 1 ) ^ { 6 } + 3 ( 1 ) ^ { 4 } - 1 ^ { 2 } + 3$$

Evaluate

$$7$$

Solution Steps

Calculate 1 to the power of 6 and get 1.

$$2\times 1+3\times 1^{4}-1^{2}+3$$

Multiply 2 and 1 to get 2.

$$2+3\times 1^{4}-1^{2}+3$$

Calculate 1 to the power of 4 and get 1.

$$2+3\times 1-1^{2}+3$$

Multiply 3 and 1 to get 3.

$$2+3-1^{2}+3$$

Add 2 and 3 to get 5.

$$5-1^{2}+3$$

Calculate 1 to the power of 2 and get 1.

$$5-1+3$$

Subtract 1 from 5 to get 4.

$$4+3$$

Add 4 and 3 to get 7.

$$7$$

Factor

$$7$$