Solve 2(0x-8)+10geq6x-18

$$2 ( 0 x - 8 ) + 10 \geq 6 x - 18$$

Solve for x

$$x\leq 2$$

Solution Steps

Anything times zero gives zero.

$$2\left(0-8\right)+10\geq 6x-18$$

Subtract 8 from 0 to get -8.

$$2\left(-8\right)+10\geq 6x-18$$

Multiply 2 and -8 to get -16.

$$-16+10\geq 6x-18$$

Add -16 and 10 to get -6.

$$-6\geq 6x-18$$

Swap sides so that all variable terms are on the left hand side. This changes the sign direction.

$$6x-18\leq -6$$

Add 18 to both sides.

$$6x\leq -6+18$$

Add -6 and 18 to get 12.

$$6x\leq 12$$

Divide both sides by 6. Since 6 is positive, the inequality direction remains the same.

$$x\leq \frac{12}{6}$$

Divide 12 by 6 to get 2.

$$x\leq 2$$