Solve 2(-6b+11)-42=10(-b-2)-8

$$2 ( - 6 b + 11 ) - 42 = 10 ( - b - 2 ) - 8$$

Solve for b

$$b=4$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by -6b+11.

$$-12b+22-42=10\left(-b-2\right)-8$$

Subtract 42 from 22 to get -20.

$$-12b-20=10\left(-b-2\right)-8$$

Use the distributive property to multiply 10 by -b-2.

$$-12b-20=10\left(-b\right)-20-8$$

Subtract 8 from -20 to get -28.

$$-12b-20=10\left(-b\right)-28$$

Subtract 10\left(-b\right) from both sides.

$$-12b-20-10\left(-b\right)=-28$$

Multiply -1 and 10 to get -10.

$$-12b-20-10\left(-1\right)b=-28$$

Multiply -10 and -1 to get 10.

$$-12b-20+10b=-28$$

Combine -12b and 10b to get -2b.

$$-2b-20=-28$$

Add 20 to both sides.

$$-2b=-28+20$$

Add -28 and 20 to get -8.

$$-2b=-8$$

Divide both sides by -2.

$$b=\frac{-8}{-2}$$

Divide -8 by -2 to get 4.

$$b=4$$