Solve 2(-6-g)>-5

$$2 ( - 6 - g ) > - 5$$

Solve for g

$$g<-\frac{7}{2}$$

Solution Steps

Divide both sides by 2. Since 2 is positive, the inequality direction remains the same.

$$-6-g>-\frac{5}{2}$$

Add 6 to both sides.

$$-g>-\frac{5}{2}+6$$

Convert 6 to fraction \frac{12}{2}.

$$-g>-\frac{5}{2}+\frac{12}{2}$$

Since -\frac{5}{2} and \frac{12}{2} have the same denominator, add them by adding their numerators.

$$-g>\frac{-5+12}{2}$$

Add -5 and 12 to get 7.

$$-g>\frac{7}{2}$$

Divide both sides by -1. Since -1 is negative, the inequality direction is changed.

$$g<\frac{\frac{7}{2}}{-1}$$

Express \frac{\frac{7}{2}}{-1} as a single fraction.

$$g<\frac{7}{2\left(-1\right)}$$

Multiply 2 and -1 to get -2.

$$g<\frac{7}{-2}$$

Fraction \frac{7}{-2} can be rewritten as -\frac{7}{2} by extracting the negative sign.

$$g<-\frac{7}{2}$$