Solve 2(-4)^4+8(-4)^3+6(-4)^2

$$2 ( - 4 ) ^ { 4 } + 8 ( - 4 ) ^ { 3 } + 6 ( - 4 ) ^ { 2 }$$

Evaluate

$$96$$

Solution Steps

Calculate -4 to the power of 4 and get 256.

$$2\times 256+8\left(-4\right)^{3}+6\left(-4\right)^{2}$$

Multiply 2 and 256 to get 512.

$$512+8\left(-4\right)^{3}+6\left(-4\right)^{2}$$

Calculate -4 to the power of 3 and get -64.

$$512+8\left(-64\right)+6\left(-4\right)^{2}$$

Multiply 8 and -64 to get -512.

$$512-512+6\left(-4\right)^{2}$$

Subtract 512 from 512 to get 0.

$$6\left(-4\right)^{2}$$

Calculate -4 to the power of 2 and get 16.

$$6\times 16$$

Multiply 6 and 16 to get 96.

$$96$$

Factor

$$2^{5}\times 3$$