Solve 2(-3)+3[4-(6(2)--3+3)]

$$2 ( - 3 ) + 3 [ 4 - ( 6 ( 2 ) - - 3 + 3 ) ]$$

Evaluate

$$-48$$

Solution Steps

Multiply 2 and -3 to get -6.

$$-6+3\left(4-\left(6\times 2-\left(-3\right)+3\right)\right)$$

Multiply 6 and 2 to get 12.

$$-6+3\left(4-\left(12-\left(-3\right)+3\right)\right)$$

The opposite of -3 is 3.

$$-6+3\left(4-\left(12+3+3\right)\right)$$

Add 12 and 3 to get 15.

$$-6+3\left(4-\left(15+3\right)\right)$$

Add 15 and 3 to get 18.

$$-6+3\left(4-18\right)$$

Subtract 18 from 4 to get -14.

$$-6+3\left(-14\right)$$

Multiply 3 and -14 to get -42.

$$-6-42$$

Subtract 42 from -6 to get -48.

$$-48$$

Factor

$$-48$$