Solve 2(-2^{2}+6^{2}-3^3)-(4^3-5^2-3^5)=

$$2 ( - 2 ^ { 2 } + 6 ^ { 2 } - 3 ^ { 3 } ) - ( 4 ^ { 3 } - 5 ^ { 2 } - 3 ^ { 5 } ) =$$

Evaluate

$$214$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$2\left(-4+6^{2}-3^{3}\right)-\left(4^{3}-5^{2}-3^{5}\right)$$

Calculate 6 to the power of 2 and get 36.

$$2\left(-4+36-3^{3}\right)-\left(4^{3}-5^{2}-3^{5}\right)$$

Add -4 and 36 to get 32.

$$2\left(32-3^{3}\right)-\left(4^{3}-5^{2}-3^{5}\right)$$

Calculate 3 to the power of 3 and get 27.

$$2\left(32-27\right)-\left(4^{3}-5^{2}-3^{5}\right)$$

Subtract 27 from 32 to get 5.

$$2\times 5-\left(4^{3}-5^{2}-3^{5}\right)$$

Multiply 2 and 5 to get 10.

$$10-\left(4^{3}-5^{2}-3^{5}\right)$$

Calculate 4 to the power of 3 and get 64.

$$10-\left(64-5^{2}-3^{5}\right)$$

Calculate 5 to the power of 2 and get 25.

$$10-\left(64-25-3^{5}\right)$$

Subtract 25 from 64 to get 39.

$$10-\left(39-3^{5}\right)$$

Calculate 3 to the power of 5 and get 243.

$$10-\left(39-243\right)$$

Subtract 243 from 39 to get -204.

$$10-\left(-204\right)$$

The opposite of -204 is 204.

$$10+204$$

Add 10 and 204 to get 214.

$$214$$

Factor

$$2\times 107$$