Solve 2(-1)^3-5x(-1/5)^-1-(4sqrt{2})^2

$$2 ( - 1 ) ^ { 3 } - 5 x ( - \frac { 1 } { 5 } ) ^ { - 1 } - ( 4 \sqrt { 2 } ) ^ { 2 }$$

Evaluate

$$25x-34$$

Solution Steps

Calculate -1 to the power of 3 and get -1.

$$2\left(-1\right)-5x\left(-\frac{1}{5}\right)^{-1}-\left(4\sqrt{2}\right)^{2}$$

Multiply 2 and -1 to get -2.

$$-2-5x\left(-\frac{1}{5}\right)^{-1}-\left(4\sqrt{2}\right)^{2}$$

Calculate -\frac{1}{5} to the power of -1 and get -5.

$$-2-5x\left(-5\right)-\left(4\sqrt{2}\right)^{2}$$

Multiply 5 and -5 to get -25.

$$-2-\left(-25x\right)-\left(4\sqrt{2}\right)^{2}$$

The opposite of -25x is 25x.

$$-2+25x-\left(4\sqrt{2}\right)^{2}$$

Expand \left(4\sqrt{2}\right)^{2}.

$$-2+25x-4^{2}\left(\sqrt{2}\right)^{2}$$

Calculate 4 to the power of 2 and get 16.

$$-2+25x-16\left(\sqrt{2}\right)^{2}$$

The square of \sqrt{2} is 2.

$$-2+25x-16\times 2$$

Multiply 16 and 2 to get 32.

$$-2+25x-32$$

Subtract 32 from -2 to get -34.

$$-34+25x$$

Expand

$$25x-34$$

Solution Steps

Calculate -1 to the power of 3 and get -1.

$$2\left(-1\right)-5x\left(-\frac{1}{5}\right)^{-1}-\left(4\sqrt{2}\right)^{2}$$

Multiply 2 and -1 to get -2.

$$-2-5x\left(-\frac{1}{5}\right)^{-1}-\left(4\sqrt{2}\right)^{2}$$

Calculate -\frac{1}{5} to the power of -1 and get -5.

$$-2-5x\left(-5\right)-\left(4\sqrt{2}\right)^{2}$$

Multiply 5 and -5 to get -25.

$$-2-\left(-25x\right)-\left(4\sqrt{2}\right)^{2}$$

The opposite of -25x is 25x.

$$-2+25x-\left(4\sqrt{2}\right)^{2}$$

Expand \left(4\sqrt{2}\right)^{2}.

$$-2+25x-4^{2}\left(\sqrt{2}\right)^{2}$$

Calculate 4 to the power of 2 and get 16.

$$-2+25x-16\left(\sqrt{2}\right)^{2}$$

The square of \sqrt{2} is 2.

$$-2+25x-16\times 2$$

Multiply 16 and 2 to get 32.

$$-2+25x-32$$

Subtract 32 from -2 to get -34.

$$-34+25x$$