Solve 2(sqrt{3}+sqrt{12})

$$2 ( \sqrt { 3 } + \sqrt { 12 } )$$

Evaluate

$$6\sqrt{3}\approx 10.392304845$$

Solution Steps

Factor 12=2^{2}\times 3. Rewrite the square root of the product \sqrt{2^{2}\times 3} as the product of square roots \sqrt{2^{2}}\sqrt{3}. Take the square root of 2^{2}.

$$2\left(\sqrt{3}+2\sqrt{3}\right)$$

Combine \sqrt{3} and 2\sqrt{3} to get 3\sqrt{3}.

$$2\times 3\sqrt{3}$$

Multiply 2 and 3 to get 6.

$$6\sqrt{3}$$