Solve 2(7/70)=-5*(7/70)^2+7*7/70+1

$$2 ( \frac { 7 } { 70 } ) = - 5 \times ( \frac { 7 } { 70 } ) ^ { 2 } + 7 \times \frac { 7 } { 70 } + 1$$

Verify

Solution Steps

Reduce the fraction \frac{7}{70} to lowest terms by extracting and canceling out 7.

$$2\times \frac{1}{10}=-5\times \left(\frac{7}{70}\right)^{2}+7\times \frac{7}{70}+1$$

Multiply 2 and \frac{1}{10} to get \frac{1}{5}.

$$\frac{1}{5}=-5\times \left(\frac{7}{70}\right)^{2}+7\times \frac{7}{70}+1$$

Reduce the fraction \frac{7}{70} to lowest terms by extracting and canceling out 7.

$$\frac{1}{5}=-5\times \left(\frac{1}{10}\right)^{2}+7\times \frac{7}{70}+1$$

Calculate \frac{1}{10} to the power of 2 and get \frac{1}{100}.

$$\frac{1}{5}=-5\times \frac{1}{100}+7\times \frac{7}{70}+1$$

Multiply -5 and \frac{1}{100} to get -\frac{1}{20}.

$$\frac{1}{5}=-\frac{1}{20}+7\times \frac{7}{70}+1$$

Reduce the fraction \frac{7}{70} to lowest terms by extracting and canceling out 7.

$$\frac{1}{5}=-\frac{1}{20}+7\times \frac{1}{10}+1$$

Multiply 7 and \frac{1}{10} to get \frac{7}{10}.

$$\frac{1}{5}=-\frac{1}{20}+\frac{7}{10}+1$$

Add -\frac{1}{20} and \frac{7}{10} to get \frac{13}{20}.

$$\frac{1}{5}=\frac{13}{20}+1$$

Add \frac{13}{20} and 1 to get \frac{33}{20}.

$$\frac{1}{5}=\frac{33}{20}$$

Least common multiple of 5 and 20 is 20. Convert \frac{1}{5} and \frac{33}{20} to fractions with denominator 20.

$$\frac{4}{20}=\frac{33}{20}$$

Compare \frac{4}{20} and \frac{33}{20}.

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