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Solve for x (complex solution)
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2t^{2}-t-1=0
Substitute t for x^{3}.
t=\frac{-\left(-1\right)±\sqrt{\left(-1\right)^{2}-4\times 2\left(-1\right)}}{2\times 2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 2 for a, -1 for b, and -1 for c in the quadratic formula.
t=\frac{1±3}{4}
Do the calculations.
t=1 t=-\frac{1}{2}
Solve the equation t=\frac{1±3}{4} when ± is plus and when ± is minus.
x=\frac{-1+\sqrt{3}i}{2} x=\frac{-\sqrt{3}i-1}{2} x=1 x=-\frac{ie^{\frac{\pi i}{6}}}{\sqrt[3]{2}} x=-\frac{1}{\sqrt[3]{2}} x=\frac{e^{\frac{\pi i}{3}}}{\sqrt[3]{2}}
Since x=t^{3}, the solutions are obtained by solving the equation for each t.
2t^{2}-t-1=0
Substitute t for x^{3}.
t=\frac{-\left(-1\right)±\sqrt{\left(-1\right)^{2}-4\times 2\left(-1\right)}}{2\times 2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. Substitute 2 for a, -1 for b, and -1 for c in the quadratic formula.
t=\frac{1±3}{4}
Do the calculations.
t=1 t=-\frac{1}{2}
Solve the equation t=\frac{1±3}{4} when ± is plus and when ± is minus.
x=1 x=-\frac{1}{\sqrt[3]{2}}
Since x=t^{3}, the solutions are obtained by evaluating x=\sqrt[3]{t} for each t.