Solve 2x^6x^3-27x^9+25x^2{x}^7

$$2 { x }^{ 6 } { x }^{ 3 } -27 { x }^{ 9 } +25 { x }^{ 2 } { x }^{ 7 }$$

Evaluate

$$0$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 6 and 3 to get 9.

$$2x^{9}-27x^{9}+25x^{2}x^{7}$$

To multiply powers of the same base, add their exponents. Add 2 and 7 to get 9.

$$2x^{9}-27x^{9}+25x^{9}$$

Combine 2x^{9} and -27x^{9} to get -25x^{9}.

$$-25x^{9}+25x^{9}$$

Combine -25x^{9} and 25x^{9} to get 0.

$$0$$

Factor

$$0$$

Solution Steps

Factor out x^{2}.

$$x^{2}\left(2x^{4}x^{3}-27x^{7}+25x^{7}\right)$$

Consider 2x^{7}-27x^{7}+25x^{7}. Factor out x^{7}.

$$0$$