Solve for Q
Q=\frac{2x^{4}}{3}-1+\frac{2}{3x}
x\neq 0
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-2x-3Qx=x-2-2x^{5}
Subtract 2x^{5} from both sides.
-3Qx=x-2-2x^{5}+2x
Add 2x to both sides.
-3Qx=3x-2-2x^{5}
Combine x and 2x to get 3x.
\left(-3x\right)Q=-2x^{5}+3x-2
The equation is in standard form.
\frac{\left(-3x\right)Q}{-3x}=\frac{-2x^{5}+3x-2}{-3x}
Divide both sides by -3x.
Q=\frac{-2x^{5}+3x-2}{-3x}
Dividing by -3x undoes the multiplication by -3x.
Q=\frac{2x^{4}}{3}-1+\frac{2}{3x}
Divide 3x-2-2x^{5} by -3x.
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