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\frac{\left(2x^{3}-x^{2}-3\right)x}{x}+\frac{9}{x}
To add or subtract expressions, expand them to make their denominators the same. Multiply 2x^{3}-x^{2}-3 times \frac{x}{x}.
\frac{\left(2x^{3}-x^{2}-3\right)x+9}{x}
Since \frac{\left(2x^{3}-x^{2}-3\right)x}{x} and \frac{9}{x} have the same denominator, add them by adding their numerators.
\frac{2x^{4}-x^{3}-3x+9}{x}
Do the multiplications in \left(2x^{3}-x^{2}-3\right)x+9.