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x\left(2x^{2}+13x+15\right)
Factor out x.
a+b=13 ab=2\times 15=30
Consider 2x^{2}+13x+15. Factor the expression by grouping. First, the expression needs to be rewritten as 2x^{2}+ax+bx+15. To find a and b, set up a system to be solved.
1,30 2,15 3,10 5,6
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 30.
1+30=31 2+15=17 3+10=13 5+6=11
Calculate the sum for each pair.
a=3 b=10
The solution is the pair that gives sum 13.
\left(2x^{2}+3x\right)+\left(10x+15\right)
Rewrite 2x^{2}+13x+15 as \left(2x^{2}+3x\right)+\left(10x+15\right).
x\left(2x+3\right)+5\left(2x+3\right)
Factor out x in the first and 5 in the second group.
\left(2x+3\right)\left(x+5\right)
Factor out common term 2x+3 by using distributive property.
x\left(2x+3\right)\left(x+5\right)
Rewrite the complete factored expression.