Solve 2x^2-xy-2=0

$$2 { x }^{ 2 } -xy-2=0$$

Solve for y

$$y=2x-\frac{2}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract 2x^{2} from both sides. Anything subtracted from zero gives its negation.

$$-xy-2=-2x^{2}$$

Add 2 to both sides.

$$-xy=-2x^{2}+2$$

The equation is in standard form.

$$\left(-x\right)y=2-2x^{2}$$

Divide both sides by -x.

$$\frac{\left(-x\right)y}{-x}=\frac{2-2x^{2}}{-x}$$

Dividing by -x undoes the multiplication by -x.

$$y=\frac{2-2x^{2}}{-x}$$

Divide -2x^{2}+2 by -x.

$$y=2x-\frac{2}{x}$$

Solve for x

$$x=\frac{\sqrt{y^{2}+16}+y}{4}$$

$$x=\frac{-\sqrt{y^{2}+16}+y}{4}$$