Factor
\frac{\left(4x-1\right)^{2}}{8}
Evaluate
\frac{\left(4x-1\right)^{2}}{8}
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\frac{16x^{2}-8x+1}{8}
Factor out \frac{1}{8}.
\left(4x-1\right)^{2}
Consider 16x^{2}-8x+1. Use the perfect square formula, a^{2}-2ab+b^{2}=\left(a-b\right)^{2}, where a=4x and b=1.
\frac{\left(4x-1\right)^{2}}{8}
Rewrite the complete factored expression.
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