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x\left(2x-4\right)=0
Factor out x.
x=0 x=2
To find equation solutions, solve x=0 and 2x-4=0.
2x^{2}-4x=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-\left(-4\right)±\sqrt{\left(-4\right)^{2}}}{2\times 2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, -4 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-\left(-4\right)±4}{2\times 2}
Take the square root of \left(-4\right)^{2}.
x=\frac{4±4}{2\times 2}
The opposite of -4 is 4.
x=\frac{4±4}{4}
Multiply 2 times 2.
x=\frac{8}{4}
Now solve the equation x=\frac{4±4}{4} when ± is plus. Add 4 to 4.
x=2
Divide 8 by 4.
x=\frac{0}{4}
Now solve the equation x=\frac{4±4}{4} when ± is minus. Subtract 4 from 4.
x=0
Divide 0 by 4.
x=2 x=0
The equation is now solved.
2x^{2}-4x=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
\frac{2x^{2}-4x}{2}=\frac{0}{2}
Divide both sides by 2.
x^{2}+\left(-\frac{4}{2}\right)x=\frac{0}{2}
Dividing by 2 undoes the multiplication by 2.
x^{2}-2x=\frac{0}{2}
Divide -4 by 2.
x^{2}-2x=0
Divide 0 by 2.
x^{2}-2x+1=1
Divide -2, the coefficient of the x term, by 2 to get -1. Then add the square of -1 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
\left(x-1\right)^{2}=1
Factor x^{2}-2x+1. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x-1\right)^{2}}=\sqrt{1}
Take the square root of both sides of the equation.
x-1=1 x-1=-1
Simplify.
x=2 x=0
Add 1 to both sides of the equation.