Solve 2x^2=7x=

$$2 { x }^{ 2 } =7x=$$

Solve for x

$$x = \frac{7}{2} = 3\frac{1}{2} = 3.5$$

$$x=0$$

Steps Using Factoring

Subtract 7x from both sides.

$$2x^{2}-7x=0$$

Factor out x.

$$x\left(2x-7\right)=0$$

To find equation solutions, solve x=0 and 2x-7=0.

$$x=0 x=\frac{7}{2}$$

Steps Using the Quadratic Formula

Subtract 7x from both sides.

$$2x^{2}-7x=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, -7 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-\left(-7\right)±\sqrt{\left(-7\right)^{2}}}{2\times 2}$$

Take the square root of \left(-7\right)^{2}.

$$x=\frac{-\left(-7\right)±7}{2\times 2}$$

The opposite of -7 is 7.

$$x=\frac{7±7}{2\times 2}$$

Multiply 2 times 2.

$$x=\frac{7±7}{4}$$

Now solve the equation x=\frac{7±7}{4} when ± is plus. Add 7 to 7.

$$x=\frac{14}{4}$$

Reduce the fraction \frac{14}{4} to lowest terms by extracting and canceling out 2.

$$x=\frac{7}{2}$$

Now solve the equation x=\frac{7±7}{4} when ± is minus. Subtract 7 from 7.

$$x=\frac{0}{4}$$

Divide 0 by 4.

$$x=0$$

The equation is now solved.

$$x=\frac{7}{2} x=0$$

Steps for Completing the Square

Subtract 7x from both sides.

$$2x^{2}-7x=0$$

Divide both sides by 2.

$$\frac{2x^{2}-7x}{2}=\frac{0}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$x^{2}-\frac{7}{2}x=\frac{0}{2}$$

Divide 0 by 2.

$$x^{2}-\frac{7}{2}x=0$$

Divide -\frac{7}{2}, the coefficient of the x term, by 2 to get -\frac{7}{4}. Then add the square of -\frac{7}{4} to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}-\frac{7}{2}x+\left(-\frac{7}{4}\right)^{2}=\left(-\frac{7}{4}\right)^{2}$$

Square -\frac{7}{4} by squaring both the numerator and the denominator of the fraction.

$$x^{2}-\frac{7}{2}x+\frac{49}{16}=\frac{49}{16}$$

Factor x^{2}-\frac{7}{2}x+\frac{49}{16}. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x-\frac{7}{4}\right)^{2}=\frac{49}{16}$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x-\frac{7}{4}\right)^{2}}=\sqrt{\frac{49}{16}}$$

Simplify.

$$x-\frac{7}{4}=\frac{7}{4} x-\frac{7}{4}=-\frac{7}{4}$$

Add \frac{7}{4} to both sides of the equation.

$$x=\frac{7}{2} x=0$$