Solve 2x^2+5y-2=0

$$2 { x }^{ 2 } +5y-2=0$$

Solve for y

$$y=\frac{2-2x^{2}}{5}$$

Steps for Solving Linear Equation

Subtract 2x^{2} from both sides. Anything subtracted from zero gives its negation.

$$5y-2=-2x^{2}$$

Add 2 to both sides.

$$5y=-2x^{2}+2$$

The equation is in standard form.

$$5y=2-2x^{2}$$

Divide both sides by 5.

$$\frac{5y}{5}=\frac{2-2x^{2}}{5}$$

Dividing by 5 undoes the multiplication by 5.

$$y=\frac{2-2x^{2}}{5}$$

Solve for x (complex solution)

$$x=-\frac{\sqrt{4-10y}}{2}$$

$$x=\frac{\sqrt{4-10y}}{2}$$

Solve for x

$$x=\frac{\sqrt{4-10y}}{2}$$

$$x=-\frac{\sqrt{4-10y}}{2}\text{, }y\leq \frac{2}{5}$$