Solve 2x^2*5=20

$$2 { x }^{ 2 } \times 5=20$$

Solve for x

$$x=\sqrt{2}\approx 1.414213562$$

$$x=-\sqrt{2}\approx -1.414213562$$

Steps by Finding Square Root

Multiply 2 and 5 to get 10.

$$10x^{2}=20$$

Divide both sides by 10.

$$x^{2}=\frac{20}{10}$$

Divide 20 by 10 to get 2.

$$x^{2}=2$$

Take the square root of both sides of the equation.

$$x=\sqrt{2} x=-\sqrt{2}$$

Steps Using the Quadratic Formula

Multiply 2 and 5 to get 10.

$$10x^{2}=20$$

Subtract 20 from both sides.

$$10x^{2}-20=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 10 for a, 0 for b, and -20 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 10\left(-20\right)}}{2\times 10}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 10\left(-20\right)}}{2\times 10}$$

Multiply -4 times 10.

$$x=\frac{0±\sqrt{-40\left(-20\right)}}{2\times 10}$$

Multiply -40 times -20.

$$x=\frac{0±\sqrt{800}}{2\times 10}$$

Take the square root of 800.

$$x=\frac{0±20\sqrt{2}}{2\times 10}$$

Multiply 2 times 10.

$$x=\frac{0±20\sqrt{2}}{20}$$

Now solve the equation x=\frac{0±20\sqrt{2}}{20} when ± is plus.

$$x=\sqrt{2}$$

Now solve the equation x=\frac{0±20\sqrt{2}}{20} when ± is minus.

$$x=-\sqrt{2}$$

The equation is now solved.

$$x=\sqrt{2} x=-\sqrt{2}$$