Solve 2e^04(x+1)-2-2e^04x-2

$$2 { e }^{ 04(x+1)-2 } -2 { e }^{ 04x-2 }$$

Evaluate

$$0$$

Solution Steps

Multiply 0 and 4 to get 0.

$$2e^{0\left(x+1\right)-2}-2e^{0\times 4x-2}$$

Anything times zero gives zero.

$$2e^{0-2}-2e^{0\times 4x-2}$$

Subtract 2 from 0 to get -2.

$$2e^{-2}-2e^{0\times 4x-2}$$

Multiply 0 and 4 to get 0.

$$2e^{-2}-2e^{0x-2}$$

Anything times zero gives zero.

$$2e^{-2}-2e^{0-2}$$

Subtract 2 from 0 to get -2.

$$2e^{-2}-2e^{-2}$$

Combine 2e^{-2} and -2e^{-2} to get 0.

$$0$$

Factor

$$0$$

Solution Steps

Factor out 2.

$$2\left(e^{-2}-e^{-2}\right)$$

Consider e^{-2}-e^{-2}. Factor out \frac{1}{e^{2}}.

$$\frac{0}{e^{2}}$$