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2\left(b^{4}-27b\right)
Factor out 2.
b\left(b^{3}-27\right)
Consider b^{4}-27b. Factor out b.
\left(b-3\right)\left(b^{2}+3b+9\right)
Consider b^{3}-27. Rewrite b^{3}-27 as b^{3}-3^{3}. The difference of cubes can be factored using the rule: p^{3}-q^{3}=\left(p-q\right)\left(p^{2}+pq+q^{2}\right).
2b\left(b-3\right)\left(b^{2}+3b+9\right)
Rewrite the complete factored expression. Polynomial b^{2}+3b+9 is not factored since it does not have any rational roots.