Solve 23^4+33^4-3^2+3

$$2 { 3 }^{ 4 } +3 { 3 }^{ 4 } - { 3 }^{ 2 } +3$$

Evaluate

$$399$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 4 to get 5.

$$2\times 3^{4}+3^{5}-3^{2}+3$$

Calculate 3 to the power of 4 and get 81.

$$2\times 81+3^{5}-3^{2}+3$$

Multiply 2 and 81 to get 162.

$$162+3^{5}-3^{2}+3$$

Calculate 3 to the power of 5 and get 243.

$$162+243-3^{2}+3$$

Add 162 and 243 to get 405.

$$405-3^{2}+3$$

Calculate 3 to the power of 2 and get 9.

$$405-9+3$$

Subtract 9 from 405 to get 396.

$$396+3$$

Add 396 and 3 to get 399.

$$399$$

Factor

$$3\times 7\times 19$$