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2\left(x^{3}+12x^{2}+48x+64\right)+1
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(x+4\right)^{3}.
2x^{3}+24x^{2}+96x+128+1
Use the distributive property to multiply 2 by x^{3}+12x^{2}+48x+64.
2x^{3}+24x^{2}+96x+129
Add 128 and 1 to get 129.
2\left(x^{3}+12x^{2}+48x+64\right)+1
Use binomial theorem \left(a+b\right)^{3}=a^{3}+3a^{2}b+3ab^{2}+b^{3} to expand \left(x+4\right)^{3}.
2x^{3}+24x^{2}+96x+128+1
Use the distributive property to multiply 2 by x^{3}+12x^{2}+48x+64.
2x^{3}+24x^{2}+96x+129
Add 128 and 1 to get 129.