Solve 2left(2+3iright)^3-9(2+3

$$2 { \left(2+3i \right) }^{ 3 } -9(2+3$$

Evaluate

$$-137+18i$$

Solution Steps

Calculate 2+3i to the power of 3 and get -46+9i.

$$2\left(-46+9i\right)-9\left(2+3\right)$$

Multiply 2 and -46+9i to get -92+18i.

$$-92+18i-9\left(2+3\right)$$

Add 2 and 3 to get 5.

$$-92+18i-9\times 5$$

Multiply 9 and 5 to get 45.

$$-92+18i-45$$

Subtract 45 from -92+18i to get -137+18i.

$$-137+18i$$

Real Part

$$-137$$

Solution Steps

Calculate 2+3i to the power of 3 and get -46+9i.

$$Re(2\left(-46+9i\right)-9\left(2+3\right))$$

Multiply 2 and -46+9i to get -92+18i.

$$Re(-92+18i-9\left(2+3\right))$$

Add 2 and 3 to get 5.

$$Re(-92+18i-9\times 5)$$

Multiply 9 and 5 to get 45.

$$Re(-92+18i-45)$$

Subtract 45 from -92+18i to get -137+18i.

$$Re(-137+18i)$$

The real part of -137+18i is -137.

$$-137$$