Solve 2*6div(3*2)^2+1-1

$$2 \times 6 \div ( 3 \times 2 ) ^ { 2 } + 1 - 1$$

Evaluate

$$\frac{1}{3}\approx 0.333333333$$

Solution Steps

Multiply 2 and 6 to get 12.

$$\frac{12}{\left(3\times 2\right)^{2}}+1-1$$

Multiply 3 and 2 to get 6.

$$\frac{12}{6^{2}}+1-1$$

Calculate 6 to the power of 2 and get 36.

$$\frac{12}{36}+1-1$$

Reduce the fraction \frac{12}{36} to lowest terms by extracting and canceling out 12.

$$\frac{1}{3}+1-1$$

Add \frac{1}{3} and 1 to get \frac{4}{3}.

$$\frac{4}{3}-1$$

Subtract 1 from \frac{4}{3} to get \frac{1}{3}.

$$\frac{1}{3}$$

Factor

$$\frac{1}{3} = 0.3333333333333333$$