Solve 2*1+3*(k+2)-(5k+1)-9=0

$$2 \times 1 + 3 \times ( k + 2 ) - ( 5 k + 1 ) - 9 = 0$$

Solve for k

$$k=-1$$

Steps for Solving Linear Equation

Multiply 2 and 1 to get 2.

$$2+3\left(k+2\right)-\left(5k+1\right)-9=0$$

Use the distributive property to multiply 3 by k+2.

$$2+3k+6-\left(5k+1\right)-9=0$$

Add 2 and 6 to get 8.

$$8+3k-\left(5k+1\right)-9=0$$

To find the opposite of 5k+1, find the opposite of each term.

$$8+3k-5k-1-9=0$$

Combine 3k and -5k to get -2k.

$$8-2k-1-9=0$$

Subtract 1 from 8 to get 7.

$$7-2k-9=0$$

Subtract 9 from 7 to get -2.

$$-2-2k=0$$

Add 2 to both sides. Anything plus zero gives itself.

$$-2k=2$$

Divide both sides by -2.

$$k=\frac{2}{-2}$$

Divide 2 by -2 to get -1.

$$k=-1$$