Solve 2*((4*2^2-1/5*2^5)-(4*0^2-1/5*0^2))-?/5=

$$2 \times ( ( 4 \times 2 ^ { 2 } - \frac { 1 } { 5 } \times 2 ^ { 5 } ) - ( 4 \times 0 ^ { 2 } - \frac { 1 } { 5 } \times 0 ^ { 2 } ) ) - \frac { ? } { 5 } =$$

Evaluate

$$19$$

Solution Steps

Calculate 2 to the power of 2 and get 4.

$$2\left(4\times 4-\frac{1}{5}\times 2^{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Multiply 4 and 4 to get 16.

$$2\left(16-\frac{1}{5}\times 2^{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Calculate 2 to the power of 5 and get 32.

$$2\left(16-\frac{1}{5}\times 32-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Multiply \frac{1}{5} and 32 to get \frac{32}{5}.

$$2\left(16-\frac{32}{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Convert 16 to fraction \frac{80}{5}.

$$2\left(\frac{80}{5}-\frac{32}{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Since \frac{80}{5} and \frac{32}{5} have the same denominator, subtract them by subtracting their numerators.

$$2\left(\frac{80-32}{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Subtract 32 from 80 to get 48.

$$2\left(\frac{48}{5}-\left(4\times 0^{2}-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Calculate 0 to the power of 2 and get 0.

$$2\left(\frac{48}{5}-\left(4\times 0-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Multiply 4 and 0 to get 0.

$$2\left(\frac{48}{5}-\left(0-\frac{1}{5}\times 0^{2}\right)\right)-\frac{1}{5}$$

Calculate 0 to the power of 2 and get 0.

$$2\left(\frac{48}{5}-\left(0-\frac{1}{5}\times 0\right)\right)-\frac{1}{5}$$

Multiply \frac{1}{5} and 0 to get 0.

$$2\left(\frac{48}{5}-\left(0-0\right)\right)-\frac{1}{5}$$

Subtracting 0 from itself leaves 0.

$$2\left(\frac{48}{5}-0\right)-\frac{1}{5}$$

Subtract 0 from \frac{48}{5} to get \frac{48}{5}.

$$2\times \frac{48}{5}-\frac{1}{5}$$

Express 2\times \frac{48}{5} as a single fraction.

$$\frac{2\times 48}{5}-\frac{1}{5}$$

Multiply 2 and 48 to get 96.

$$\frac{96}{5}-\frac{1}{5}$$

Since \frac{96}{5} and \frac{1}{5} have the same denominator, subtract them by subtracting their numerators.

$$\frac{96-1}{5}$$

Subtract 1 from 96 to get 95.

$$\frac{95}{5}$$

Divide 95 by 5 to get 19.

$$19$$

Factor

$$19$$