Solve 2*(1/x^-8)+(1/frac{1{x^7}})

$$2 \times ( \frac { 1 } { x ^ { - 8 } } ) + ( \frac { 1 } { \frac { 1 } { x ^ { 7 } } } )$$

Evaluate

$$\left(2x+1\right)x^{7}$$

Short Solution Steps

Express 2\times \frac{1}{x^{-8}} as a single fraction.

$$\frac{2}{x^{-8}}+\frac{1}{\frac{1}{x^{7}}}$$

Divide 1 by \frac{1}{x^{7}} by multiplying 1 by the reciprocal of \frac{1}{x^{7}}.

$$\frac{2}{x^{-8}}+x^{7}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply x^{7} times \frac{x^{-8}}{x^{-8}}.

$$\frac{2}{x^{-8}}+\frac{x^{7}x^{-8}}{x^{-8}}$$

Since \frac{2}{x^{-8}} and \frac{x^{7}x^{-8}}{x^{-8}} have the same denominator, add them by adding their numerators.

$$\frac{2+x^{7}x^{-8}}{x^{-8}}$$

Do the multiplications in 2+x^{7}x^{-8}.

$$\frac{2+\frac{1}{x}}{x^{-8}}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 2 times \frac{x}{x}.

$$\frac{\frac{2x}{x}+\frac{1}{x}}{x^{-8}}$$

Since \frac{2x}{x} and \frac{1}{x} have the same denominator, add them by adding their numerators.

$$\frac{\frac{2x+1}{x}}{x^{-8}}$$

Express \frac{\frac{2x+1}{x}}{x^{-8}} as a single fraction.

$$\frac{2x+1}{xx^{-8}}$$

To multiply powers of the same base, add their exponents. Add 1 and -8 to get -7.

$$\frac{2x+1}{x^{-7}}$$

Factor

$$\left(2x+1\right)x^{7}$$