Solve 2*[6^2:(35-11)+1^3]

$$2 \times [ 6 ^ { 2 } : ( 35 - 11 ) + 1 ^ { 3 } ]$$

Evaluate

$$5$$

Solution Steps

Calculate 6 to the power of 2 and get 36.

$$2\left(\frac{36}{35-11}+1^{3}\right)$$

Subtract 11 from 35 to get 24.

$$2\left(\frac{36}{24}+1^{3}\right)$$

Reduce the fraction \frac{36}{24} to lowest terms by extracting and canceling out 12.

$$2\left(\frac{3}{2}+1^{3}\right)$$

Calculate 1 to the power of 3 and get 1.

$$2\left(\frac{3}{2}+1\right)$$

Convert 1 to fraction \frac{2}{2}.

$$2\left(\frac{3}{2}+\frac{2}{2}\right)$$

Since \frac{3}{2} and \frac{2}{2} have the same denominator, add them by adding their numerators.

$$2\times \frac{3+2}{2}$$

Add 3 and 2 to get 5.

$$2\times \frac{5}{2}$$

Cancel out 2 and 2.

$$5$$

Factor

$$5$$