Solve 2*2+sqrt{16}-4^6div4^5=

$$2 \times 2+ \sqrt{ 16 } - { 4 }^{ 6 } \div { 4 }^{ 5 } =$$

Evaluate

$$4$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 5 from 6 to get 1.

$$2\times 2+\sqrt{16}-4^{1}$$

Multiply 2 and 2 to get 4.

$$4+\sqrt{16}-4^{1}$$

Calculate the square root of 16 and get 4.

$$4+4-4^{1}$$

Add 4 and 4 to get 8.

$$8-4^{1}$$

Calculate 4 to the power of 1 and get 4.

$$8-4$$

Subtract 4 from 8 to get 4.

$$4$$

Factor

$$2^{2}$$