Solve 2*-2/3-7-3*-2/3-5=

$$2 \times - \frac{ 2 }{ 3 } -7-3 \times - \frac{ 2 }{ 3 } -5=$$

Evaluate

$$-\frac{34}{3}\approx -11.333333333$$

Solution Steps

Express 2\left(-\frac{2}{3}\right) as a single fraction.

$$\frac{2\left(-2\right)}{3}-7-3\left(-\frac{2}{3}\right)-5$$

Multiply 2 and -2 to get -4.

$$\frac{-4}{3}-7-3\left(-\frac{2}{3}\right)-5$$

Fraction \frac{-4}{3} can be rewritten as -\frac{4}{3} by extracting the negative sign.

$$-\frac{4}{3}-7-3\left(-\frac{2}{3}\right)-5$$

Convert 7 to fraction \frac{21}{3}.

$$-\frac{4}{3}-\frac{21}{3}-3\left(-\frac{2}{3}\right)-5$$

Since -\frac{4}{3} and \frac{21}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-4-21}{3}-3\left(-\frac{2}{3}\right)-5$$

Subtract 21 from -4 to get -25.

$$-\frac{25}{3}-3\left(-\frac{2}{3}\right)-5$$

Cancel out 3 and 3.

$$-\frac{25}{3}-\left(-2\right)-5$$

The opposite of -2 is 2.

$$-\frac{25}{3}+2-5$$

Convert 2 to fraction \frac{6}{3}.

$$-\frac{25}{3}+\frac{6}{3}-5$$

Since -\frac{25}{3} and \frac{6}{3} have the same denominator, add them by adding their numerators.

$$\frac{-25+6}{3}-5$$

Add -25 and 6 to get -19.

$$-\frac{19}{3}-5$$

Convert 5 to fraction \frac{15}{3}.

$$-\frac{19}{3}-\frac{15}{3}$$

Since -\frac{19}{3} and \frac{15}{3} have the same denominator, subtract them by subtracting their numerators.

$$\frac{-19-15}{3}$$

Subtract 15 from -19 to get -34.

$$-\frac{34}{3}$$

Factor

$$-\frac{34}{3} = -11\frac{1}{3} = -11.333333333333334$$