Solve 2*(x-3)-3*(x-5)=4*(3-x)-18

$$2 \times (x-3)-3 \times (x-5)=4 \times (3-x)-18$$

Solve for x

$$x=-5$$

Steps for Solving Linear Equation

Use the distributive property to multiply 2 by x-3.

$$2x-6-3\left(x-5\right)=4\left(3-x\right)-18$$

Use the distributive property to multiply -3 by x-5.

$$2x-6-3x+15=4\left(3-x\right)-18$$

Combine 2x and -3x to get -x.

$$-x-6+15=4\left(3-x\right)-18$$

Add -6 and 15 to get 9.

$$-x+9=4\left(3-x\right)-18$$

Use the distributive property to multiply 4 by 3-x.

$$-x+9=12-4x-18$$

Subtract 18 from 12 to get -6.

$$-x+9=-6-4x$$

Add 4x to both sides.

$$-x+9+4x=-6$$

Combine -x and 4x to get 3x.

$$3x+9=-6$$

Subtract 9 from both sides.

$$3x=-6-9$$

Subtract 9 from -6 to get -15.

$$3x=-15$$

Divide both sides by 3.

$$x=\frac{-15}{3}$$

Divide -15 by 3 to get -5.

$$x=-5$$