Solve 2*4^3-12*4^2+x*4=0

$$2 \times { 4 }^{ 3 } -12 \times { 4 }^{ 2 } +x \times 4=0$$

Solve for x

$$x=16$$

Steps for Solving Linear Equation

Calculate 4 to the power of 3 and get 64.

$$2\times 64-12\times 4^{2}+x\times 4=0$$

Multiply 2 and 64 to get 128.

$$128-12\times 4^{2}+x\times 4=0$$

Calculate 4 to the power of 2 and get 16.

$$128-12\times 16+x\times 4=0$$

Multiply 12 and 16 to get 192.

$$128-192+x\times 4=0$$

Subtract 192 from 128 to get -64.

$$-64+x\times 4=0$$

Add 64 to both sides. Anything plus zero gives itself.

$$x\times 4=64$$

Divide both sides by 4.

$$x=\frac{64}{4}$$

Divide 64 by 4 to get 16.

$$x=16$$