Solve 2*3^5+2*3^4+0*3+0*3^2+1*3^0=

$$2 \times { 3 }^{ 5 } +2 \times { 3 }^{ 4 } +0 \times 3+0 \times { 3 }^{ 2 } +1 \times { 3 }^{ 0 } =$$

Evaluate

$$649$$

Solution Steps

Calculate 3 to the power of 5 and get 243.

$$2\times 243+2\times 3^{4}+0\times 3+0\times 3^{2}+1\times 3^{0}$$

Multiply 2 and 243 to get 486.

$$486+2\times 3^{4}+0\times 3+0\times 3^{2}+1\times 3^{0}$$

Calculate 3 to the power of 4 and get 81.

$$486+2\times 81+0\times 3+0\times 3^{2}+1\times 3^{0}$$

Multiply 2 and 81 to get 162.

$$486+162+0\times 3+0\times 3^{2}+1\times 3^{0}$$

Add 486 and 162 to get 648.

$$648+0\times 3+0\times 3^{2}+1\times 3^{0}$$

Multiply 0 and 3 to get 0.

$$648+0+0\times 3^{2}+1\times 3^{0}$$

Add 648 and 0 to get 648.

$$648+0\times 3^{2}+1\times 3^{0}$$

Calculate 3 to the power of 2 and get 9.

$$648+0\times 9+1\times 3^{0}$$

Multiply 0 and 9 to get 0.

$$648+0+1\times 3^{0}$$

Add 648 and 0 to get 648.

$$648+1\times 3^{0}$$

Calculate 3 to the power of 0 and get 1.

$$648+1\times 1$$

Multiply 1 and 1 to get 1.

$$648+1$$

Add 648 and 1 to get 649.

$$649$$

Factor

$$11\times 59$$