Solve 2*2^4+0*2^3+3*2^2+3*2+0=

$$2 \times { 2 }^{ 4 } +0 \times { 2 }^{ 3 } +3 \times { 2 }^{ 2 } +3 \times 2+0=$$

Evaluate

$$50$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 4 to get 5.

$$2^{5}+0\times 2^{3}+3\times 2^{2}+3\times 2+0$$

Calculate 2 to the power of 5 and get 32.

$$32+0\times 2^{3}+3\times 2^{2}+3\times 2+0$$

Calculate 2 to the power of 3 and get 8.

$$32+0\times 8+3\times 2^{2}+3\times 2+0$$

Multiply 0 and 8 to get 0.

$$32+0+3\times 2^{2}+3\times 2+0$$

Add 32 and 0 to get 32.

$$32+3\times 2^{2}+3\times 2+0$$

Calculate 2 to the power of 2 and get 4.

$$32+3\times 4+3\times 2+0$$

Multiply 3 and 4 to get 12.

$$32+12+3\times 2+0$$

Add 32 and 12 to get 44.

$$44+3\times 2+0$$

Multiply 3 and 2 to get 6.

$$44+6+0$$

Add 44 and 6 to get 50.

$$50+0$$

Add 50 and 0 to get 50.

$$50$$

Factor

$$2\times 5^{2}$$