Solve 2*2^3*-3+3*2^2*4

$$2 \times { 2 }^{ 3 } \times -3+3 \times { 2 }^{ 2 } \times 4$$

Evaluate

$$0$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$2^{4}\left(-3\right)+3\times 2^{2}\times 4$$

Calculate 2 to the power of 4 and get 16.

$$16\left(-3\right)+3\times 2^{2}\times 4$$

Multiply 16 and -3 to get -48.

$$-48+3\times 2^{2}\times 4$$

Calculate 2 to the power of 2 and get 4.

$$-48+3\times 4\times 4$$

Multiply 3 and 4 to get 12.

$$-48+12\times 4$$

Multiply 12 and 4 to get 48.

$$-48+48$$

Add -48 and 48 to get 0.

$$0$$

Factor

$$0$$