Solve 2*1^5-8*1^4+3*1^3+2*1^2-7*1+8

$$2 \times { 1 }^{ 5 } -8 \times { 1 }^{ 4 } +3 \times { 1 }^{ 3 } +2 \times { 1 }^{ 2 } -7 \times 1+8$$

Evaluate

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Solution Steps

Calculate 1 to the power of 5 and get 1.

$$2\times 1-8\times 1^{4}+3\times 1^{3}+2\times 1^{2}-7\times 1+8$$

Multiply 2 and 1 to get 2.

$$2-8\times 1^{4}+3\times 1^{3}+2\times 1^{2}-7\times 1+8$$

Calculate 1 to the power of 4 and get 1.

$$2-8\times 1+3\times 1^{3}+2\times 1^{2}-7\times 1+8$$

Multiply 8 and 1 to get 8.

$$2-8+3\times 1^{3}+2\times 1^{2}-7\times 1+8$$

Subtract 8 from 2 to get -6.

$$-6+3\times 1^{3}+2\times 1^{2}-7\times 1+8$$

Calculate 1 to the power of 3 and get 1.

$$-6+3\times 1+2\times 1^{2}-7\times 1+8$$

Multiply 3 and 1 to get 3.

$$-6+3+2\times 1^{2}-7\times 1+8$$

Add -6 and 3 to get -3.

$$-3+2\times 1^{2}-7\times 1+8$$

Calculate 1 to the power of 2 and get 1.

$$-3+2\times 1-7\times 1+8$$

Multiply 2 and 1 to get 2.

$$-3+2-7\times 1+8$$

Add -3 and 2 to get -1.

$$-1-7\times 1+8$$

Multiply 7 and 1 to get 7.

$$-1-7+8$$

Subtract 7 from -1 to get -8.

$$-8+8$$

Add -8 and 8 to get 0.

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Factor

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