Solve for θ
\theta =-\frac{\sqrt{3}}{3}\approx -0.577350269
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2\theta =-\frac{2\sqrt{3}}{\left(\sqrt{3}\right)^{2}}
Rationalize the denominator of \frac{2}{\sqrt{3}} by multiplying numerator and denominator by \sqrt{3}.
2\theta =-\frac{2\sqrt{3}}{3}
The square of \sqrt{3} is 3.
6\theta =-2\sqrt{3}
Multiply both sides of the equation by 3.
\frac{6\theta }{6}=-\frac{2\sqrt{3}}{6}
Divide both sides by 6.
\theta =-\frac{2\sqrt{3}}{6}
Dividing by 6 undoes the multiplication by 6.
\theta =-\frac{\sqrt{3}}{3}
Divide -2\sqrt{3} by 6.
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